An ideal gas is taken through  cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are Q₁ = 5970 J, Q₂ = -5485 J, Q₃ = -2900 J, Q₄ = 3650 J, respectively. The corresponding works involved are W₁ = 2500 J, W₂ = -725 J, W₃ = -1200 J and W₄, respectively. The value of W₄ is : 

660 J

\(\Delta Q = Q_1 + Q_2 + Q_3 + Q_4\)

\(\Delta Q = 5970 - 5485 - 2900 + 3650 \) = 1235 J

\(\Delta W = W_1 + W_2 + W_3 + W_4\)

\(\Delta W = 2500 - 725 - 1200 + W_4\) = 575 + W₄

For a cyclic process : U_f = U_i

\(\Delta U = U_f - U_i\) = 0

From First Law of Thermodynamics : \(\Delta Q = \Delta U + \Delta W\)

1235 + 0 = 575 + W₄ 

\(\Rightarrow W_4 = 660\) J