Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Numbers, Quantification and Numerical Applications

Question:

In a 300 m race, A reaches the finish point in 20 sec and B reaches in 25 sec. By how much distance A beats B ?

Options:

50 m

60 m

75 m

40 m

Correct Answer:

60 m

Explanation:

The correct answer is Option (2) → 60 m

Speed of A = $\frac{300m}{20s}=15m/s$

Speed of B = $\frac{300m}{25s}=12m/s$

Distance covered by B in 20 seconds = $12×20=240m$

The distance A beats B by = $(300-240)m=60m$