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a b c d |
c |
The correct answer is Option (3) → c $2\begin{bmatrix}1&3\\0&x\end{bmatrix}+\begin{bmatrix}y&0\\1&2\end{bmatrix}=\begin{bmatrix}5&6\\1&8\end{bmatrix}$ $\begin{bmatrix}2+y&6\\1&2x+2\end{bmatrix}=\begin{bmatrix}5&6\\1&8\end{bmatrix}$ $⇒2x+2=8$ $⇒2x=6$ $⇒x=3$ |