Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Numbers, Quantification and Numerical Applications

Question:

If t(n) = Number of positive divisors of n, n ∈ N, then what is the value of $t(36)$?

Options:

10

8

9

7

Correct Answer:

9

Explanation:

The correct answer is option (2) : 9

$36=1×36$

$36=2×18$

$36=3×12$

$36=4×9$

So, +ve divisions of $36=1,2, 3, 4, 6, 9, 12, 18 ,36$

$∴t(28)= 9$