Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Linear Programming

Question:

The feasible region for an LPP is shown below. Let $Z=3x-4y$ be the objective functions. Maximum of Z occurs at :

 

Options:

(0, 6)

(5, 4)

(4, 8)

(4, 0)

Correct Answer:

(4, 0)

Explanation:

The correct answer is option (4) → (4, 0)

Points  Value of $Z=3x-4y$
$A(0,6)$   $Z_A=-24$
$B(4,8)$ $Z_B=-20$
$C(5,6)$ $Z_C=-9$
$D(5,4)$ $Z_D=-1$
$E(4,0)$ $Z_E=12$

$Z_E=12 → Z_{max}$

$E(4,0)$ → point of maxima