Practicing Success
If cosec θ - cot θ = \(\frac{7}{2}\), then value of cos θ = ? |
\(\frac{45}{53}\) \(\frac{28}{53}\) \(\frac{53}{45}\) \(\frac{53}{28}\) |
\(\frac{45}{53}\) |
If cosec θ - cot θ = \(x\), then cosec θ + cot θ = \(\frac{1}{x}\) ATQ, ⇒ cosec θ - cot θ = \(\frac{7}{2}\) ..........(i) ⇒ cosec θ + cot θ = \(\frac{2}{7}\) ..........(ii) (i) + (ii) ⇒ 2 cosec θ = \(\frac{7}{2}\) + \(\frac{2}{7}\) = \(\frac{49 + 4}{14}\) = \(\frac{53}{14}\) ⇒ cosec θ= \(\frac{53 (H)}{28 (P)}\) H2 = P2 + B2 ⇒ (53)2 = (28)2 + B2 ⇒ B = 45 Hence, cos θ = \(\frac{B}{H}\) = \(\frac{45}{53}\) |