Match List - I with List - II.
|
List – I |
List – II |
|
(A) Electric potential (V) due to a single charge |
(I) $∝r^0$ |
|
(B) Electric flux due to a positive point charge through sphere of radius r |
(II) $∝\frac{1}{r^2}$ |
|
(C) Electric intensity (E) due to a point charge |
(III) $∝\frac{1}{r}$ |
|
(D) Electric intensity (E) due to dipole |
(IV) $∝\frac{1}{r^3}$ |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
(A) Electric potential due to a single charge = $\frac{1}{4πε_0}\frac{q}{r}=∝\frac{1}{r}$ (III)
(B) Electric flux due to a positive charge through a surface = $\phi_{E}=\frac{Q(=1)}{ε_0}⇒∝r^0$ (I)
(C) Electric intensity due to a point charge, $E=\frac{1}{4πε_0}\frac{q(=1)}{r^2}⇒∝\frac{1}{r^2}$ (II)
(D) Electric intensity due to a dipole = $E∝\frac{1}{r^3}$ (IV)