Match List - I with List - II.
Choose the correct answer from the options given below: |
(A)-(IV), (B)-(II), (C)-(III), (D)-(I) (A)-(III), (B)-(I), (C)-(II), (D)-(IV) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
(A)-(III), (B)-(I), (C)-(II), (D)-(IV) |
The correct answer is Option (2) → (A)-(III), (B)-(I), (C)-(II), (D)-(IV) (A) Electric potential due to a single charge = $\frac{1}{4πε_0}\frac{q}{r}=∝\frac{1}{r}$ (III) (B) Electric flux due to a positive charge through a surface = $\phi_{E}=\frac{Q(=1)}{ε_0}⇒∝r^0$ (I) (C) Electric intensity due to a point charge, $E=\frac{1}{4πε_0}\frac{q(=1)}{r^2}⇒∝\frac{1}{r^2}$ (II) (D) Electric intensity due to a dipole = $E∝\frac{1}{r^3}$ (IV) |