Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Time, Speed and Distance

Question:

Ina 1200 m race, bike A beats bike B by 100 m. Bike beats like C by 100 m in a 600 m race. If bike A beats like C by 30 sec in a 720 m race, then what is the speed of bike C ?

Options:

$\frac{17}{3}$ m/sec

$\frac{26}{9}$ m/sec

$\frac{17}{9}$ m/sec

$\frac{26}{3}$ m/sec

Correct Answer:

$\frac{17}{3}$ m/sec

Explanation:

In a 1200 m race, bike A beats bike B by 100 m

Ratio of       A      :    B

Distance    1200  :   1100

Speed         12    :   11

( Ratio of distance and speed is same )

Bike B beats bike C by 100 m in a 600 m race.

Ratio of       B      :    C

Distance      600  :   500

Speed           6    :   5

( Ratio of distance and speed is same )

Overall ,   A  :  B   :  C

              72  : 66  :  55

According to question,

72R = 720 m

1R = 10 m

Now, Distance cover by C = 55 x 10 = 550 m

Difference in distance covered by them = 720 - 550 = 170 m

Bike C cover this 170 m in 30 sec.

Speed of C = \(\frac{170}{30}\)

= \(\frac{17}{3}\) m/sec