The amount of ammonium sulphate required to prepare 2 litres of 1 molar solution is:
Answer & explanation
Correct answer: option 1
The correct answer is option 1. 264 g.
Molar mass of ammonium sulphate \(= 132 g/mol\)
Volume = \(2 L\)
Molarity \(= 1\)
\(Weight = \text{Molarity × Molar mass of ammonium sulphate × volume}\)
\(Weight = 1 × 132 × 2 = 264 g\)