Practicing Success
The amount of ammonium sulphate required to prepare 2 litres of 2 molar solution is: |
264 g 132 g 198 g 212 g |
264 g |
The correct answer is option 1. 264 g. Molar mass of ammonium sulphate \(= 132 g/mol\) Volume = \(2 L\) Molarity \(= 1\) \(Weight = \text{Molarity × Molar mass of ammonium sulphate × volume}\) \(Weight = 1 × 132 × 2 = 264 g\) |