If a + b + c = 6, a2 + b2 + c2 = 14 and ab + bc + ca = 11, then what is the value of a3 + b3 + c3 - 3abc?
Answer & explanation
Correct answer: option 3
If a + b + c = 6
a2 + b2 + c2 = 14
ab + bc + ca = 11
then what is the value of a3 + b3 + c3 - 3abc?
a3 + b3 + c3 - 3abc = ( a + b + c ) ( a2 + b2 + c2 - (ab + bc + ca))
a3 + b3 + c3 - 3abc = 6 ( 14 - (11)) = 18