If a + b + c = 6, a2 + b2 + c2 = 14 and

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If a + b + c = 6, a² + b² + c² = 14 and ab + bc + ca = 11, then what is the value of a³ + b³ + c³ - 3abc?

Options:

Correct Answer:

Explanation:

If a + b + c = 6

a² + b² + c² = 14

ab + bc + ca = 11

then what is the value of a³ + b³ + c³ - 3abc?

a³ + b³ + c³ - 3abc = ( a + b + c ) ( a² + b² + c² - (ab + bc + ca))

a³ + b³ + c³ - 3abc = 6 ( 14 - (11)) = 18