Two rotating bodies A and B of masses m and 2m with moments of inertia IA and IB (IB > IA) have equal kinetic energy of rotation. If LA and LB be their angular momenta respectively, then :

LA = \(\frac{L_B}{2}\) LA = \(2L_B\) LB > LA LA > LB

LB > LA

Energy : E = \(\frac{L^2}{2I}\) Given : EA = EB \(\frac{L_A^2}{2I_A}\) = \(\frac{L_B^2}{2I_B}\) As (IB > IA) ⇒ LB > LA