Two rotating bodies A and B of masses m and 2m with moments of inertia IA and IB (IB > IA) have equal kinetic energy of rotation. If LA and LB be their angular momenta respectively, then :
Answer & explanation
Correct answer: option 3
Energy : E = \(\frac{L^2}{2I}\)
Given : EA = EB
\(\frac{L_A^2}{2I_A}\) = \(\frac{L_B^2}{2I_B}\)
As (IB > IA) ⇒ LB > LA