Arrange the following events of human embryo development in a correct sequence:
(A) Blastocyst formation
(B) Implantation
(C) Formation of morula
(D) Cleavage in zygote
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (D), (C), (A), (B)
(D) Cleavage in zygote — first. The zygote divides by mitosis into 2, 4, 8, 16 blastomeres as it moves down the fallopian tube.
(C) Formation of morula — second. The embryo with 8–16 blastomeres is the morula.
(A) Blastocyst formation — third. The morula becomes a blastocyst, with an outer trophoblast and an inner cell mass.
(B) Implantation — last. The blastocyst gets embedded in the endometrium of the uterus.
NCERT Extract:
Fertilisation and Implantation – “… The mitotic division starts as the zygote moves through the isthmus of the oviduct called cleavage towards the uterus (Figure 2.11) and forms 2, 4, 8, 16 daughter cells called blastomeres. The embryo with 8 to 16 blastomeres is called a morula (Figure 2.11e). The morula continues to divide and transforms into blastocyst (Figure 2.11g) as it moves further into the uterus. The blastomeres in the blastocyst are arranged into an outer layer called trophoblast and an inner group of cells attached to trophoblast called the inner cell mass. The trophoblast layer then gets attached to the endometrium and the inner cell mass gets differentiated as the embryo. After attachment, the uterine cells divide rapidly and covers the blastocyst. As a result, the blastocyst becomes embedded in the endometrium of the uterus (Figure 2.11 step H). This is called implantation and it leads to pregnancy.”