Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

Which of the following functions is a solution to the differential equation \[y = { e }^{ \frac{-ax}{b} } \]

Options:

\[y'' - \frac{ { a }^{ 2 } }{ { b }^{ 2 } }y= 0\]

\[y''+\frac{ { a }^{ 2 } }{ { b }^{ 2 } }y= 0\]

Both of the differential equations mentioned above.

None of the differential equations mentioned above.

Correct Answer:

\[y'' - \frac{ { a }^{ 2 } }{ { b }^{ 2 } }y= 0\]

Explanation:

\(y = { e }^{ \frac{-ax}{b} } \)

\(y'' = \frac{ { a }^{ 2 } }{ { b }^{ 2 } } { e }^{ \frac{-ax}{b} } \])