According to Bohr's model, the radius of the second orbit of helium atom is
Answer & explanation
Correct answer: option 2
$r=\frac{n^2}{Z}\left(r_0\right) ; \Rightarrow r_{(n=2)}=\frac{(2)^2}{2} \times 0.53=1.06 Å$
According to Bohr's model, the radius of the second orbit of helium atom is
Correct answer: option 2
$r=\frac{n^2}{Z}\left(r_0\right) ; \Rightarrow r_{(n=2)}=\frac{(2)^2}{2} \times 0.53=1.06 Å$