Battery acid is 4.27 M H₂SO₄ (aq) and has the density of 1.25 g/ml. What is the molality of H₂SO₄ in the solution?

5.135 m

4.27 M H₂SO₄ (aq) solution means 4.27 moles of H₂SO₄ are present in 1000 mL of solution.

Mass of solution = denisty x volume = 1.25 x 1000 = 1250 g

Mass of 4.27 mole of H₂SO₄ = 4.27 x 98 = 418.46 g

Mass of water present = 1250 - 418.46 = 831.54 g

Molality, m= \(\frac{4.27}{831.54}\) x 1000 = 5.135 m