Match List-I with List-II (take \(\pi=\frac{22}{7}\)).
| List-I (Solid) | List-II (Volume) | ||
|---|---|---|---|
| (A) | Cube of edge 5 cm | (I) | 125 cm3 |
| (B) | Cuboid of length 8 cm, breadth 5 cm and height 3 cm | (II) | 66 cm3 |
| (C) | Cylinder of radius 7 cm and height 2 cm | (III) | 120 cm3 |
| (D) | Cone of radius 3 cm and height 7 cm | (IV) | 308 cm3 |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → (A)-(I), (B)-(III), (C)-(IV), (D)-(II)
Use the volume formula of each solid: cube \(a^3\), cuboid \(l\times b\times h\), cylinder \(\pi r^2h\), cone \(\frac{1}{3}\pi r^2h\).
(A) Cube: \(5^3=125\) cm3 → (I)
(B) Cuboid: \(8\times5\times3=120\) cm3 → (III)
(C) Cylinder: \(\frac{22}{7}\times7\times7\times2=308\) cm3 → (IV)
(D) Cone: \(\frac{1}{3}\times\frac{22}{7}\times3\times3\times7=66\) cm3 → (II)
So the matching is (A)-(I), (B)-(III), (C)-(IV), (D)-(II).