CUET Preparation Today
If cot θ = $\sqrt{2}+1$, then cosec θ sec θ = ? |
$\frac{\sqrt{2}}{2}$ $\frac{\sqrt{2}}{4}$ $2\sqrt{2}$ $4\sqrt{2}$ |
$2\sqrt{2}$ |
cot θ = \(\frac{√2 + 1}{1}\) { we know, cot θ = \(\frac{B}{P}\) } By using pythagoras theorem , P² + B² = H² 1² + (√2 + 1)² = H² H² = 4 + 2√2 Now, cosecθ . secθ = \(\frac{H}{P}\) . \(\frac{H}{B}\) = \(\frac{4 + 2√2}{√2 + 1}\) = 2√2 |
