If cot θ = √2+1, then cosec θ sec θ = ?

cot θ = \(\frac{√2 + 1}{1}\)

{ we know, cot θ = \(\frac{B}{P}\) }

By using pythagoras theorem ,

P² + B² = H²

1² + (√2 + 1)² = H²

H² = 4 + 2√2

Now,

cosecθ . secθ

= \(\frac{H}{P}\) . \(\frac{H}{B}\)

= \(\frac{4 + 2√2}{√2 + 1}\)

= 2√2