ΔABC ∼ ΔRQP and AB = 6 cm, BC = 8 cm and AC = 12 cm.  If ratio of area of ΔABC and ΔPQR = 16 : 9, then PQ is equal to?

\(\frac{81}{4}\)cm 8 cm 6 cm 25 cm

6 cm

\(\frac{area\;of\;ΔABC}{area\;of\;ΔPQR}\) = \(\frac{16}{9}\) \(\frac{BC^2}{PQ^2}\) = \(\frac{16}{9}\) \(\frac{64}{PQ^2}\) = \(\frac{16}{9}\) PQ = 6 cm