ΔABC ∼ ΔRQP and AB = 6 cm, BC = 8 cm and AC = 12 cm. If ratio of area of ΔABC and ΔPQR = 16 : 9, then PQ is equal to?
Answer & explanation
Correct answer: option 3
\(\frac{area\;of\;ΔABC}{area\;of\;ΔPQR}\) = \(\frac{16}{9}\)
\(\frac{BC^2}{PQ^2}\) = \(\frac{16}{9}\)
\(\frac{64}{PQ^2}\) = \(\frac{16}{9}\)
PQ = 6 cm