Electric field $\vec{E}$ at the surface of charged conductor is: A. $|\vec{E}|=\frac{\sigma}{\varepsilon_0}$ Choose the correct answer from the options given below: |
C only C and E only A, B and C only A, C and D only |
A, C and D only |
The correct answer is Option (4) → A, C and D only (A) The electric field at the surface of a charged conductor is - $|E|=\frac{σ}{ε_0}$ (C) In electrostatic equilibrium, the electric field inside a conductor is always zero, if there were field inside, free charges would move until it become nullity. (D) In electrostatic any excess charge on a conductor radistributes itself to reside on the surface to minimize repulsion. |