CUET Preparation Today
In a transistor amplifier, $β = 62$, $R_L = 5000 Ω$ and internal resistance of the transistor is 500 . The voltage amplification of the amplifier will be: |
500 620 780 950 |
620 |
Voltage amplification = $\frac{βR_L}{R_e}=\frac{62×5000}{500}=620$ |
