CUET Preparation Today
$\alpha=\frac{F}{v^2}sin(\beta t)$.Then dimensions of $\alpha$ is |
[MLT] $[ML^{-1}T^0]$ $[ML^0T]$ $[MLT^2]$ |
$[ML^{-1}T^0]$ |
$sin(\beta t)$ is dimensionless. So dimension of $\alpha$ is same as dimension of $\frac{F}{V^2}$ = $\frac{[MLT^{-2}]}{[L^2T^{-2}]}$ = $[ML^{-1}T^0]$ |
