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The function $f(x)=xe^x$ increases only for : |
$x≤1$ $x≥1$ $x≤-1$ $x≥-1$ |
$x≥-1$ |
The correct answer is Option (4) → $x≥-1$ $f(x)=xe^x$ so $f'(x)=e^x+xe^x=0⇒x=-1$ so for $x≥-1$ f(x) is increasing |
