The function $f(x)=xe^x$ increases only for :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $x≥-1$
$f(x)=xe^x$
so $f'(x)=e^x+xe^x=0⇒x=-1$
so for $x≥-1$
f(x) is increasing
The function $f(x)=xe^x$ increases only for :
Correct answer: option 4
The correct answer is Option (4) → $x≥-1$
$f(x)=xe^x$
so $f'(x)=e^x+xe^x=0⇒x=-1$
so for $x≥-1$
f(x) is increasing