The oxidation number of cobalt in K3[Co(NO2)6] is:
Answer & explanation
Correct answer: option 2
The correct answer is option 2. \(+3\).
The given complex is \(K_3[Co(NO_2)_6]\)
The oxidation number of \(K\) is \(+1\)
The oxidation number of the \(NO_2^-\) ligand is \(-1\).
Let the oxidation number of \(Co\) be \(x\)
Since, the complex is neutral, so the total charge is \(0\).
Thus,
\(3(+1) + x + 6(-1) = 0\)
\(⇒ +3 + x - 6 = 0\)
\(⇒ x - 3 = 0\)
\(⇒ x = +3\)