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The domain of the function $f(x) = sin^{-1}(2x-3)$, is |
[-1,1] [-5,-1] [1,2] [-2,2] |
[1,2] |
The domain of $sin^{-1}$ x is [-1,1]. Therefore, $f(x) = sin^{-1}(2x-3)$ is defined for all x satisfying $-1 ≤ 2x - 3 ≤ 1 ⇒ 3-1 ≤ 2x ≤ 3+1 ⇒1 ≤ x ≤ 2 ⇒ x ∈ [1,2]$ Hence, domain of f(x) = $sin^{-1}(2x-3) $ is [1,2] |
