The total cost C(x) in Rupees associated with the production of x units of an item is given by $C(x) = 0.007x^3+26x^2+15x+400$. The marginal cost when 10 items are produced is:

₹537.1

The correct answer is Option (1) → ₹537.1

$C(x)=0.007x^{3}+26x^{2}+15x+400$

Marginal cost $MC(x)=C'(x)$

$C'(x)=0.021x^{2}+52x+15$

At $x=10$:

$MC(10)=0.021(10^{2})+52(10)+15$

$=0.021\cdot 100 + 520 + 15$

$=2.1 + 520 + 15$

$=537.1$

$537.1$ Rupees