The total cost C(x) in Rupees associated with the production of x units of an item is given by $C(x) = 0.007x^3+26x^2+15x+400$. The marginal cost when 10 items are produced is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → ₹537.1
$C(x)=0.007x^{3}+26x^{2}+15x+400$
Marginal cost $MC(x)=C'(x)$
$C'(x)=0.021x^{2}+52x+15$
At $x=10$:
$MC(10)=0.021(10^{2})+52(10)+15$
$=0.021\cdot 100 + 520 + 15$
$=2.1 + 520 + 15$
$=537.1$
$537.1$ Rupees