Find the length of the diagonal of a closed cube whose total surface area is 96 m2.

$8 \sqrt{3}$ m $4 \sqrt{3}$ m $2 \sqrt{3}$ m 4 m

$4 \sqrt{3}$ m

We know that, Diagonal of cube = \(\sqrt {3}\) × Side of cube The total surface area of a cube = 6a2 ( If a is the side ) We have, The total surface area of the room = 96 m2 6a2 = 96 = a2 = 16 = a = 4 The length of the diagonal of the cube = 4\(\sqrt {3}\) m.