The value of $Δ=\begin{bmatrix}b-c & c-a & a-b\\c-a & a-b & b-c\\a-b & b-c & c-a\end{bmatrix}$ is
Answer & explanation
Correct answer: option 2
The correct answer is option (2) : 0
Applying $C_1→C_1+C_2+C_3, $ we have
$Δ=\begin{bmatrix}0 & c-a & a-b\\0 & a-b & b-c\\0 & b-c & c-a\end{bmatrix}=0 $ [∵ $C_1$ consists of all zeroes]