A car manufacturing plant produces Sedans and SUV's, using limited resources of steel, labour hours, and machine hours.

• Each Sedan requires 6 tons of steel, 10 labour hours and 8 machine hours.
• Each SUV requires 9 tons of steel, 15 labour hours and 12 machine hours.
• Plant has 600 tons of steel, 1200 labour hours and 1000 machine hours.
• Profit per Sedan is Rs. 50,000 and per SUV is Rs. 80,000

The optimal Profit is,

52,80,000

The correct answer is Option (4) → 52,80,000

Z optimal is at (0, 66).

$⇒Z(0,66)=50,000×0+80,000×66$

$=52,80,000$