The equation of the tangent line to the curve \(y = x^2 - 2x + 5\) which is parallel to the line \(4x - y + 1 = 0\) is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \(4x-y-4=0\)
The line \(4x - y + 1 = 0\), that is \(y = 4x + 1\), has slope 4. Parallel lines have equal slopes, so the tangent has slope 4:
\( \displaystyle \frac{dy}{dx} = 2x - 2 = 4 \)
\(x = 3,\quad y = 9 - 6 + 5 = 8\)
The tangent at (3, 8) with slope 4:
\(y - 8 = 4(x - 3)\)
\(y = 4x - 4\)
\(4x - y - 4 = 0\)
Note: This topic was not in the CUET 2026 syllabus.