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The range of the function $y=\frac{x}{1+x^2}$ is |
$\left(-\frac{1}{2},\frac{1}{2}\right)$ $\left(-\frac{1}{2},\frac{1}{2}\right]$ $\left[-\frac{1}{2},\frac{1}{2}\right)$ $\left[-\frac{1}{2},\frac{1}{2}\right]$ |
$\left[-\frac{1}{2},\frac{1}{2}\right]$ |
y = 0 at x = 0 and for x ≠ 0 $y=\frac{x}{1+x^2}$ or $yx^2 − x + y = 0$ $∴x=\frac{1±\sqrt{1-4y^2}}{2y}$ Since x is real, the range of the function y is determined from the relation $1-4y^2 ≥ 0, -\frac{1}{2}≤y≤\frac{1}{2}$. |
