Arrange the following in the increasing order of de-Broglie wavelength:

A. A bullet of mass 0.02 kg travelling at the speed of 3.3 Km/s.
B. A ball of mass 0.0331 kg moving with speed of 2 m/s.
C. A dust particle of mass 2 × 10^-10 Kg drifting with a speed of 3.3 m/s.
D. A photon having a momentum of 6.63 × 10^-26 kg m/s.
E. An electron accelerated through a potential difference of 100 V.

Choose the correct answer from the options given below:

A < B < C < E < D

$\lambda = \frac{h}{mv}$

$ \lambda \propto \frac{1}{mv}$

A. $mv = 66 Kg - m/s $

B . $mv = 0.066 Kg - m /s $

C . $ mv = 6.6 \times 10^{-10} Kg - m/s$

D . $ mv = 6.63\times 10^{-26} Kg - m /s $

E . $ mv = \sqrt{2mqV} = \sqrt{ 2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 100} = 5.4 \times 10^{-24} Kg-m/s$

Hence order of wavelength is A < B < C < E < D