CUET Preparation Today
If y = \( { x }^{ 4 } - k { x }^{ 3 } \) then for what value of x, we have \(\frac{d^3 y}{dx^3}\) = 0? |
0 \[\frac{k}{4}\] Both 0 and \(\frac{k}{2}\) Neither 0 nor \(\frac{k}{2}\) |
\[\frac{k}{4}\] |
\(\frac{d^3 y}{dx^3}\) = 24x - 6kk |
