Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

A function $f$ is defined by $f(x)=2+(x-1)^{2 / 3}$ on $[0,2]$. Which of the following is not correct?

Options:

$f$ is not derivable in $(0,2)$

$f$ is continuous in $[0,2]$

$f(0)=f(2)$

Rolle's theorem is applicable on $[0,2]$

Correct Answer:

Rolle's theorem is applicable on $[0,2]$

Explanation:

We have,

$f(x)=2+(x-1)^{2 / 3} \Rightarrow f^{\prime}(x)=\frac{2}{3(x-1)^{1 / 3}}$

Clearly, $f(x)$ is not differentiable at $x=1$.

So, Rolle's theorem is not applicable on $[0,2]$.