Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Options:

a

b

c

d

Correct Answer:

d

Explanation:

$ E = -\frac{dV}{dx} = -\frac{20\times -2x}{(x^2-4)^2}$

$ \text{ At x = }4\mu m ,  E = \frac{10}{9} V/\mu m $

$\text{E is along +ve X-Axis}$