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The value of $cos^{-1}(cos\frac{7\pi}{6})$ is : |
$\frac{7\pi }{6}$ $\frac{5\pi }{6}$ $\frac{\pi }{6}$ $\frac{\pi }{3}$ |
$\frac{5\pi }{6}$ |
The correct answer is Option (2) → $\frac{5\pi }{6}$ $\cos^{-1}(\cos\frac{7\pi}{6})=\cos^{-1}(-\cos\frac{\pi}{6})$ $=π-\frac{π}{6}=\frac{5π}{6}$ |
