The value of $cos^{-1}(cos\frac{7\pi}{6})$ is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{5\pi }{6}$
$\cos^{-1}(\cos\frac{7\pi}{6})=\cos^{-1}(-\cos\frac{\pi}{6})$
$=π-\frac{π}{6}=\frac{5π}{6}$
The value of $cos^{-1}(cos\frac{7\pi}{6})$ is :
Correct answer: option 2
The correct answer is Option (2) → $\frac{5\pi }{6}$
$\cos^{-1}(\cos\frac{7\pi}{6})=\cos^{-1}(-\cos\frac{\pi}{6})$
$=π-\frac{π}{6}=\frac{5π}{6}$