The work done in moving a point charge, $2 \mu C$ between two points between which the potential difference is 50 V is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $10^{-4} J$
The work done, W in moving a point charge q between two points with potential difference ΔV is -
$W=qΔV$
$W=2×10^{-6}×50$
$=100×10^{-6}=10^{-4}J$