The area of the region bounded by the lines $x = 2y+3, x = 0, y = 1$ and $y = -1$ is:

4 sq. units 6 sq. units 8 sq. units $\frac{3}{2}$ sq. units

6 sq. units

Integrating along y axis from $y=-1$ to $y=1$ we get, Area = $\int_{-1}^12y+3dy$ $=[y^2+3y]_{-1}^1$ $=3(1)-3(-1)=6$ sq. units