The area of the region bounded by the lines $x = 2y+3, x = 0, y = 1$ and $y = -1$ is:
Answer & explanation
Correct answer: option 2
Integrating along y axis from $y=-1$ to $y=1$
we get,
Area = $\int_{-1}^12y+3dy$
$=[y^2+3y]_{-1}^1$
$=3(1)-3(-1)=6$ sq. units