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| The coordinates of the point, where the line \(\frac{x-2}{-1}=\frac{y+3}{1}=\frac{z-1}{6}\) intersects the plane \(2x+y+z=7\), are |
\((2,1,-7)\) \((7,-1,2)\) \((1,-2,7)\) \((2,-7,1)\) |
| \((1,-2,7)\) |
| Assume \(\frac{x-2}{-1}=\frac{y+3}{1}=\frac{z-1}{6}=k\), Find values of \(x,y\) and \(z\) and put these values in plane. |
