If in a Triangle PQR, AngleP = 88o , PQ and PR produced to point S and T respectively. If the bisectors of angle SQR and TRQ meet at the point O. Find angle QOR.

44o 46o 48o 42o

46o

\(\angle\)QOR = 90 - \(\frac{88}{2}\) = 90 - 44 = 46 Therefore, \(\angle\)QOR is 46.