A chord 10 cm long is drawn in a circle of diameter 26 cm. The perpendicular distance of the chord from the centre is:
Answer & explanation
Correct answer: option 1
We know that,
Diameter of circle = 26 cm
Radius OA = 13 cm
Length of chord AB = 10 cm
then, AC = 5 cm
Using Pythagorean Theorem,
OA2 = OC2 + AC2
⇒ 132 = OC2 + 52
⇒ 169 = OC2 + 25
⇒ OC2 = 144
⇒ OC = 12 cm