Practicing Success
Practicing Success
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500 J of work is done in sliding a 2.5 kg block up an inclined plane of height 10 m. Taking g =10 m/s2, work done against friction is : |
750 J 250 J 550 J 300 J |
250 J |
Work-Energy theorem : W = \(\Delta\) KE \(\Delta\) KE = 0 500 – Wgravity – Wfriction = 0 Wgravity = mgh = 2.5m*10m/s2*10m = 250 J ⇒ Wfriction = 250 J |
