Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Probability Distributions

Question:

The probability distribution of a random variable X is given as:

X

0

1

2

3

4

 P(X) 

 k 

 2k 

 4k 

 6k 

 7k 

The mean of the distribution is:

Options:

$\frac{14}{5}$

$\frac{14}{3}$

$\frac{3}{4}$

$\frac{17}{6}$

Correct Answer:

$\frac{14}{5}$

Explanation:

The correct answer is Option (1) → $\frac{14}{5}$