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CUET
-- Mathematics - Section B2
Probability Distributions
The probability distribution of a random variable X is given as:
X
0
1
2
3
4
P(X)
k
2k
4k
6k
7k
The mean of the distribution is:
$\frac{14}{5}$
$\frac{14}{3}$
$\frac{3}{4}$
$\frac{17}{6}$
The correct answer is Option (1) → $\frac{14}{5}$