If x lies in [0, 1], then minimum value of x2 + x + 1 is
Answer & explanation
Correct answer: option 2
$f(x)=x^2+x+1 \Rightarrow f'(x) 2 x+1>0$ for $x \in[0, 1]$
∴ f(x) is monotonically increasing on [0, 1]
∴ Min. value of f(x) is f(0) = 1
If x lies in [0, 1], then minimum value of x2 + x + 1 is
Correct answer: option 2
$f(x)=x^2+x+1 \Rightarrow f'(x) 2 x+1>0$ for $x \in[0, 1]$
∴ f(x) is monotonically increasing on [0, 1]
∴ Min. value of f(x) is f(0) = 1