The equation of the line (in Cartesian form) which passes through the point (-2, 4, 5) and parallel to the line given by $\frac{(x+3)}{3}=\frac{(y-4)}{5}=\frac{(z+8)}{6}$ is :

$\frac{x+2}{3}=\frac{y-4}{4}=\frac{z-5}{6}$

The correct answer is Option (1) → $\frac{x+2}{3}=\frac{y-4}{4}=\frac{z-5}{6}$

parallel vectors direction ratios → 3, 4, 6

Eq. of line: $\frac{x+2}{3}=\frac{y-4}{4}=\frac{z-5}{6}$