Ajay bought two tables for ₹5400. He sold one at a loss of 5% and the other at a gain of 7%. If there is no profit no loss in the whole transaction, then what are the costs of the two tables?
Answer & explanation
Correct answer: option 2
Let CP of one table = Rs. X
SP of 1st table at a loss of 5% = \(\frac{95}{100}\)X
CP of other table = ( 5400 - X )
SP of other table at a loss of 7% = \(\frac{107}{100}\) ( 5400 - X )
As there is no loss or gain ,
Total CP = Total SP
5400 = \(\frac{95}{100}\)X + \(\frac{107}{100}\) ( 5400 - X )
5400 = \(\frac{95}{100}\)X - \(\frac{107}{100}\)X + \(\frac{107 × 5400}{100}\)
5400 = - \(\frac{12}{100}\)X + \(\frac{107 × 5400}{100}\)
- \(\frac{12}{100}\)X = 5400 - \(\frac{107 × 5400}{100}\)
- \(\frac{12}{100}\)X = \(\frac{ 5400 × 100 - 107 × 5400}{100}\)
- \(\frac{12}{100}\)X = \(\frac{ 540000 - 577800}{100}\)
-12x = -37800
x = \(\frac{37800}{12}\)
= 3150
CP of other table = ( 5400 - X )= 5400 - 3150 = 2250
The correct answer is Option (2) → ₹3150, ₹2250