Ajay bought two tables for ₹5400. He sold one at a loss of 5% and the other at a gain of 7%. If there is no profit no loss in the whole transaction, then what are the costs of the two tables?

₹3150, ₹2250

Let CP of one table = Rs. X

SP of 1st table at a loss of 5% = \(\frac{95}{100}\)X

CP of other table = ( 5400 - X )

SP of other table at a loss of 7% = \(\frac{107}{100}\) ( 5400 - X )

As there is no loss or gain ,

Total CP = Total SP

5400 = \(\frac{95}{100}\)X + \(\frac{107}{100}\) ( 5400 - X )

5400 = \(\frac{95}{100}\)X - \(\frac{107}{100}\)X + \(\frac{107 × 5400}{100}\)

5400 = - \(\frac{12}{100}\)X + \(\frac{107 × 5400}{100}\)

- \(\frac{12}{100}\)X = 5400 - \(\frac{107 × 5400}{100}\)

- \(\frac{12}{100}\)X =  \(\frac{ 5400 × 100 -  107 × 5400}{100}\)

- \(\frac{12}{100}\)X =  \(\frac{ 540000 -  577800}{100}\)

-12x = -37800

x = \(\frac{37800}{12}\)

= 3150

CP of other table = ( 5400 - X )= 5400 - 3150 = 2250

The correct answer is Option (2) → ₹3150, ₹2250