Practicing Success
A Circuit contains two inductors of self inductance L1 and L2 in series. If M is the mutual inductance, then the effective inductance of the circuit will be |
L1+L2 L1+L2 -2M L1+L2 +M L1+L2 +2M |
L1+L2 +2M |
when inductances are connected like this in series, then L = L1+L2+2M |