Practicing Success
Practicing Success
CUET Preparation Today
The average of the first nine integral multiples of 3 is: |
9 135 15 30 |
15 |
3 6 9 -----------------------------27 Average = \(\frac{1st\;+\;Last}{2}\) = \(\frac{3\;+\;27}{2}\) ⇒ 15 |
