If the square of product of three sides of the triangle is 1024 units and the area of its circumcircle is 16π . What is the are of the given triangle?
Answer & explanation
Correct answer: option 1
We know that,
R = \(\frac{ abc }{4Area}\)
Area of circle = πr2
We have,
The product of the three sides of the triangle = 1024 units
Area of circle = πR2
16π = πR2
R = 4
(abc)2 = 1024
(abc) = 32
So, R = \(\frac{ abc }{4Area}\) = \(\frac{ 32 }{4Area}\)
4 = \(\frac{ 32 }{4Area}\)
Area = 2
We know that,
R = \(\frac{ abc }{4Area}\)
Area of circle = πr2
We have,
The product of the three sides of the triangle = 1024 units
Area of circle = πR2
16π = πR2
R = 4
(abc)2 = 1024
(abc) = 32
So, R = \(\frac{ abc }{4Area}\) = \(\frac{ 32 }{4Area}\)
4 = \(\frac{ 32 }{4Area}\)
A = 2