If the square of product of three sides of the triangle is 1024 units and the area of its circumcircle is 16π . What is the are of the given triangle?

2 sq. units

We know that,

R = \(\frac{ abc }{4Area}\)

Area of circle = πr²

We have,

The product of the three sides of the triangle = 1024 units

Area of circle = πR²

16π = πR²

R = 4

(abc)² = 1024

(abc) = 32

So, R = \(\frac{ abc }{4Area}\) = \(\frac{ 32 }{4Area}\)

4 = \(\frac{ 32 }{4Area}\)

Area = 2

We know that,

R = \(\frac{ abc }{4Area}\)

Area of circle = πr²

We have,

The product of the three sides of the triangle = 1024 units

Area of circle = πR²

16π = πR²

R = 4

(abc)² = 1024

(abc) = 32

So, R = \(\frac{ abc }{4Area}\) = \(\frac{ 32 }{4Area}\)

4 = \(\frac{ 32 }{4Area}\)

A = 2