For the cell represented by the followin

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Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Electro Chemistry

Question:

For the cell represented by the following reaction

$Mg(s) + 2Ag^+ (0.0001M) → Mg^{2+} (0.2M) + 2Ag(s)$

If $E^°_{(cell)} = 3.17 V$, its $E_{(cell)}$ at $298\, K$ will be:

(Given: $\log_{10} 2 = 0.301$)

Options:

2.96 V

2.42 V

1.94 V

4.5 V

Correct Answer:

2.96 V

Explanation:

The correct answer is Option (1) → 2.96 V