Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Logical and Analytical Reasoning

Topic

Calendar

Question:

On 7th March, 2005 Monday falls. What was the day of the week on 7th March 2004?

Options:

Monday 

Saturday 

Sunday 

Friday 

Correct Answer:

Sunday 

Explanation:

\(\frac{Date + Month\;code + Century\;code + Century\;upper\;year + Quotient\;of\;\frac{upper\;year}{4}}{7}\) 

\(\frac{7 + 3 + 6 + 5 + 1}{7}\) = \(\frac{22}{7}\) = Remainder 1

The day for Code 1 is Monday. So, it is the same day which is given on 7th March, 2005

therefore,

The day for 7th March, 2004 was :

\(\frac{Date + Month\;code + Century\;code + Century\;upper\;year + Quotient\;of\;\frac{upper\;year}{4}}{7}\) 

\(\frac{7 + 3 + 6 + 4 + 1}{7}\) = \(\frac{21}{7}\) = Remainder 0

The day for Code 0 is Sunday. 

 

Note:     

Code for      Mon – 1      Tues – 2      Wed – 3      Thurs – 4

                   Fri – 5         Sat ­­– 6        Sun – 0

Code for      Jan – 0        Apr – 6       July – 6       Oct – 0

                   Feb – 3       May – 1      Aug – 2       Nov – 3

                   Mar – 3       June – 4      Sep – 5       Dec – 5

Code for     

1900 is 0

2000 is 6

2100 is 4

2200 is 2

2300 is 0

2400 is 6

2500 is 4   and  Likewise